F(x)=2x^2-5x+8

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Solution for F(x)=2x^2-5x+8 equation: 



(F)=2F^2-5F+8

We move all terms to the left:

(F)-(2F^2-5F+8)=0

We get rid of parentheses

-2F^2+F+5F-8=0

We add all the numbers together, and all the variables

-2F^2+6F-8=0

a = -2; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·(-2)·(-8)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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